Acetonitrile on reduction with $L i A l H_{4}$ will give

C H_{3} N H_{2}

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C H_{3} C H_{2} N H_{2}

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C H_{3} C H = N H

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C H_{3} N H C H_{3}

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Solution

The correct option is B $C H_{3} C H_{2} N H_{2}$
Acetonitrile on reduction with $L i A l H_{4}$ will give $C H_{3} C H_{2} N H_{2}$ .

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