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Distinguishing Test of Terminal and Non Terminal Alkynes

Acetylene rea...

Question

Acetylene reacts with ammoniacal $A g N O_{3}$ forming

A

Silver acetylene

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B

Silver acetate

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C

Disilver acetylide.

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D

Silver mirror

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Solution

The correct option is C Disilver acetylide.
Acetylene reacts with ammoniacal silver nitrate to produce disilver acetylide.
$C H \equiv C H \to + 2 [A g (N H_{3})_{2}] N O_{3} \to + A g - C \equiv C^{-} A g^{+}$

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Q. Acetylene reacts with ammoniacal

A g N O_{3}

Q. Acetylene reacts with ammoniacal

A g N O_{3}

Q. Acetylene reacts with ammonical

A g N O_{3}

(C_{5} H_{8})

reacts with ammoniacal

A g N O_{3}

to give a white precipitate and reacts with excess of

K M n O_{4}

solution to give

(C H_{3})_{2} C H C O O H

. The compound is:

^{'} X^{'}

having molecular formula

C_{5} H_{8}

, reacts with ammoniacal

A g N O_{3}

to give a white precipitate and reacts with excess of

K M n O_{4}

to give the acid,

(C H_{3})_{2} C H - C O O H

X

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Distinguishing Test of Terminal and Non Terminal Alkynes

Standard XIII Chemistry

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