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Standard XIII

Chemistry

Distinguishing Test of Terminal and Non Terminal Alkynes

Acetylene rea...

Question

Acetylene reacts with ammoniacal $A g N O_{3}$ forming

Silver acetylene

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Silver acetate

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Disilver acetylide.

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Solution

The correct option is C Disilver acetylide.
Acetylene reacts with ammoniacal silver nitrate to produce disilver acetylide.
$C H \equiv C H \to + 2 [A g (N H_{3})_{2}] N O_{3} \to + A g - C \equiv C^{-} A g^{+}$

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Similar questions

Q. Acetylene reacts with ammoniacal

A g N O_{3}

forming

Q. Acetylene reacts with ammonical

A g N O_{3}

, forming:

Q. A compound

(C_{5} H_{8})

reacts with ammoniacal

A g N O_{3}

to give a white precipitate and reacts with excess of

K M n O_{4}

solution to give

(C H_{3})_{2} C H C O O H

. The compound is:

Q. A compound

^{'} X^{'}

having molecular formula

C_{5} H_{8}

, reacts with ammoniacal

A g N O_{3}

to give a white precipitate and reacts with excess of

K M n O_{4}

to give the acid,

(C H_{3})_{2} C H - C O O H

. Therefore,

X

is:

Q. Deduce the structural of a compound A

(C_{6} H_{10})

which shows the following reactions.
i. Adds 2 mol of

H_{2}

to form 2-methyl pentane.
ii. Reacts with aqueous

H_{2} S O_{4} + H g S O_{4}

solution to give a carbonyl compound.
iii. Does not react with ammoniacal

A g N O_{3}

solution.

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Distinguishing Test of Terminal and Non Terminal Alkynes

Standard XIII Chemistry

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Acetylene reacts with ammoniacal AgNO3 forming

The correct option is C Disilver acetylide.Acetylene reacts with ammoniacal silver nitrate to produce disilver acetylide. CH≡CH→+2[Ag(NH3)2]NO3→+Ag−C≡C−Ag+

Acetylene reacts with ammoniacal $A g N O_{3}$ forming

The correct option is C Disilver acetylide.
Acetylene reacts with ammoniacal silver nitrate to produce disilver acetylide.
$C H \equiv C H \to + 2 [A g (N H_{3})_{2}] N O_{3} \to + A g - C \equiv C^{-} A g^{+}$