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Avogadro's Law & Gay Lussac's Law

Acetylene, us...

Question

Acetylene, used as a fuel in welding torches, is produced in a reaction between calcium carbide and water:
$C a C_{2} + 2 H_{2} O \to C a {(O H)}_{2} + C_{2} H_{2}$
How many grams of $C_{2} H_{2}$ are formed from 0.400 moles of $C a C_{2}$ ?

0.400

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0.800

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4.00

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10.4

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26.0

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Solution

The correct option is D $10.4$
$C a C_{2} + 2 H 2 O \to C a (O H)_{2} + C_{2} H_{2}$
As per this balanced chemical equation 1 mol of $C_{2} H_{2}$ produces 1 mol of $C_{2} H_{2}$ .
0.400 mol of $C a C_{2}$ will produce 0.400 mol of $C_{2} H_{2}$ .
As 1 mol of $C_{2} H_{2}$ has 26 g weight.
Hence, 0.400 mol produced has weight to be equal to the $0.4 \times 26 = 10.4$ g.

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