Acetylene when reacts with two molecules of HBr, it gives :

B r - C \equiv C - B r

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B r - C H = C H - B r

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Solution

The correct option is D
When acetylene react with one mole of HBr it gives electrophilic addition product 1-Bromoethene.
The formed unsymmetrical alkene will react with another mole of HBr to give the product.
The addition of HBr to an unsymmetrical alkene obeys Markovnikov's rule.

Markovnikov's rule : Negative part of the addendum (adding molecule) gets attached to that doubly bonded C which posses lesser number of hydrogen atoms.

Here, Negative part of HBr i.e., $B r^{-}$ get attached to the doubly bonded carbon which posses lesser number of hydrogen atoms to give major product.

$C H \equiv C H H B r - -- \to C H_{2} = C H B r H B r - ------------ \to M a r k o v n i k o v a d d i t i o n C H_{3} C H B r_{2}$

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