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Question

Acid and water are mixed in a vessel A in the ratio of 5:2 and in the vessel B in the ratio of 8:5. In what proportion should quantities be taken out from the two vessels so as to form a mixture in which the acid and water will be in the ratio of 9:4?

A
7:2
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B
2:7
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C
7:4
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D
2:3
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Solution

The correct option is A 7:2
Acid and water are mixed in veuel A inb the ratio of 5:2 and in the veuel B in the raio of 8:5 In what propartion on should quantites taken out from the two veuel So as the to from a mixture in which the acid water will be in the ratio of 9:97
In veuel A= Acid:Water=5:2
In veuel B - Acid:Water = 8:5
By the mixture and alligation formula
Therefore required ratio =113:291
=7:2

1374753_1162228_ans_da4fdd2b27a84a9cba08c37a79ec73e5.png

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