Question

Acid and water are mixed in a vessel A in the ratio of 5:2 and in the vessel B in the ratio of 8:5. In what proportion should quantities be taken out from the two vessels so as to form a mixture in which the acid and water will be in the ratio of 9:4?

• A. 7:2
• B. 2:7
• C. 7:4
• D. 2:3

Answer 1

The correct option is A 7:2

Acid and water are mixed in veuel $A$ inb the ratio of $5:2$ and in the veuel $B$ in the raio of $8:5$ In what propartion on should quantites taken out from the two veuel So as the to from a mixture in which the acid water will be in the ratio of $9:97$

In veuel $A$= Acid:Water=$5:2$

In veuel $B$ - Acid:Water = $8:5$

By the mixture and alligation formula

Therefore required ratio $=\frac{1}{13}:\frac{2}{91}$

$=7:2$