Question

Across a $2H$ inductor, the potential difference as a function of time is as shown in figure.

• A. Currect at $t=2s$ is $4A$
• B. Currect at $t=2s$ is $5A$
• C. Current versus time graph across the inductor will be ,
  
• D. Current versus time graph across the conductor will be ,
  

Answer 1

Answer: (B), (D)

The correct options are
B Currect at $t=2s$ is $5A$
D Current versus time graph across the conductor will be ,


$V_L=L\frac{di}{dt}\text{or Ldi}=V_{L}dt$
$\therefore L[I_f-I_i]=\text{Area under}{V}_L\text{vs t graph}$
$\Rightarrow 2[i_f-0]=\frac{1}{2}\left(10\right)\times 2=10\Rightarrow i_f=5\text{A}$

For the first 2 seconds the slope of current is increasing and for the next 2 seconds, the slope of current is decreasing. Option (4), shows the same behaviour.