Question

The potential difference across a $150mH$ inductor as a function of time is shown in figure. Assume that the initial value of the current in the inductor is zero. What is the current when $t=2.0ms$?

Answer 1

$V_L=L\frac{di}{dt}$
$\therefore di=\frac{1}{L}\left(V_{L}dt\right)$
$\therefore \int di=i=\frac{1}{L}\int V_{L}dt$
At $t=2ms$
$i={(150\times {10}^{-3})}^{-1}(\frac{1}{2}\times 2\times {10}^{-3}\times 5)=3.33\times {10}^{-2}A$