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$7 x^{3} + 2 x^{2} - 5 x - 7 & - 5 x^{2} + x^{3} + 4 x - 5$

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Solution

$(7 x^{3} + 2 x^{2} - 5 x - 7) + (- 5 x^{2} + x^{3} + 4 x - 5) = (7 x^{3} + x^{3}) + (2 x^{2} - 5 x^{2}) + (- 5 x + 4 x) + (- 7 - 5)$
$= 8 x^{3} - 3 x^{2} - x - 12$

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What must be subtracted from $4 x^{3} - 3 x + 5$ to get $2 x^{2} - 3 x^{3} + 5 x - 2$ ?

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