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Question

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tt214, 15t3+13+9t8t2, 12t21924t and 4t9t2+19t3.

If t=1 find the value of the expression. [4 MARKS]

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Solution

Forming equation: 1 Mark
Steps: 1 Mark
Answer: 1 Mark
Value: 1 Mark

Here while adding the algebraic expressions we need to know that we can only add the like terms.
Like terms are those terms which have the same algebraic factors.

Sum

=(tt214)+(15t3+13+9t8t2)+(12t21924t)+(4t9t2+19t3)
=tt214+15t3+13+9t8t2+12t21924t+4t9t2+19t3
=(t+9t24t+4t)+(t28t2+12t29t2)+(14+1319)+(15t3+19t3)
=10t6t220+34t3

Hence, the required expression is 10t6t220+34t3.

Given that:
t=1
On substituting the values we get:
10t6t220+34t3
=10×(1)6×(1)220+34×(1)3
=1062034
=50


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