If g - t2-3 - 4t-1-2- what is the value of g when t - 64- 33-2257-1631-216

The correct option is A 33/2 g=t^2/3 + 4t^ 1/2 =t^2/3+ 4 ×1/t^1/2 =(64)^2/3 + 4×1/64^1/2 =(4^3)^2/3 + 4 ×1/(8^2)^1/2 =4^2+4×1/8^2×1/2=4^2+4/8 = 16 + 1/2=3 ...

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Byju's Answer

Standard IX

Mathematics

Laws of Exponents for Real Numbers

If g = t2/3 +...

Question

If g = $t^{\frac{2}{3}} + 4 t^{\frac{- 1}{2}}$ , what is the value of g when t = 64?

$\frac{31}{2}$

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$\frac{33}{2}$

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$\frac{257}{16}$

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Solution

The correct option is B
$\frac{33}{2}$

$g = t^{\frac{2}{3}} + 4 t^{\frac{- 1}{2}} = t^{\frac{2}{3}} + 4 \times \frac{1}{t^{\frac{1}{2}}} = (64)^{\frac{2}{3}} + 4 \times \frac{1}{64^{\frac{1}{2}}} = (4^{3})^{\frac{2}{3}} + 4 \times \frac{1}{(8^{2})^{\frac{1}{2}}} = 4^{2} + 4 \times \frac{1}{8^{2 \times \frac{1}{2}}} = 4^{2} + \frac{4}{8} = 16 + \frac{1}{2} = \frac{33}{2}$

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Similar questions

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If g = t23+4t−12, what is the value of g when t = 64?

The correct option is B 332 g=t23+4t−12=t23+4×1t12=(64)23+4×16412=(43)23+4×1(82)12=42+4×182×12=42+48=16+12=332

If g = $t^{\frac{2}{3}} + 4 t^{\frac{- 1}{2}}$ , what is the value of g when t = 64?