Add the following:
5abc,-3abc,2abc,8abc
Given, polynomial are 5abc,-3abc,2abc,8abc.
Adding the given terms,
=5abc+(-3abc)+2abc+8abc=(5-3+2+8)abc=12abc
Hence, the sum of 5abc,-3abc,2abc,8abc is 12abc.
If a+b+c=0 then (a3+b3+c3) is (a) 0 (b) abc (c) 2abc (d) 3abc
Add the terms: -2abc,3abc,abc
Question 81 (i)
Add :
7a2bc,−3abc2,3a2bc,2abc2
Add the terms: 2abc,3bacand7cab