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Question

Add the following polynomials.
(i) x29x+3:19x+3+7x2
(ii)2ab2+3a2b4ab;3ab8ab2+2a2b

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Solution

(i)
Given x29x+3+(19x+3+7x2)
=x29x+319x+3+7x2
=x2+7x29x19x+3+3
=8x228x+23

(ii)
Given (2ab2+3a2b4ab)+(3ab8ab2+2a2b)
=2ab2+3a2b4ab+3ab8ab2+2a2b
=2ab28ab2+3a2b+2a2b4ab+3ab
=6ab2+5a2bab

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