5xy+(−2xy)+(−11xy)+8xy
=5xy−2xy−11xy+8xy
=(5−2−11+8)xy [Taking out the common variables]
=(0)xy
=0
∴5xy+(−2xy)+(−11xy)+8xy=0
4xy−5yz−7z
–5xy+2yz+zx
–2xy−3yz+3zx
------------------------------
Find the product of 11xy2 and−8xy3.