Question

Add. Write each sum in the lowest terms.

$$\begin{gathered} \frac{1}{2} \\ +\frac{1}{6} \\ \_\_\_\_\_ \end{gathered}$$

Answer 1

If the denominators are different, we change to equivalent fractions that have the same denominator.

Also, if one denominator is a multiple of the other, the greater number can be used as a common denominator.

$$\begin{gathered} =\frac{1}{2}+\frac{1}{6} \\ =\frac{3}{6}+\frac{1}{6}(Changing\frac{1}{2}toequivalentfractionthathavesamedenominator) \\ =\frac{3+1}{6} \\ =\frac{4}{6}(dividingnumerator\&denominatorbycommonfactor2) \\ =\frac{2}{3} \end{gathered}$$

Therefore the required sum in the lowest term is $\frac{2}{3}$