Question

Add. Write each sum in the lowest terms.

$$\begin{gathered} \frac{2}{9} \\ +\frac{2}{3} \\ \_\_\_\_\_ \end{gathered}$$

Answer 1

If the denominators are different, we change to equivalent fractions that have the same denominator.

Also, if one denominator is a multiple of the other, the greater number can be used as a common denominator.

$$\begin{gathered} =\frac{2}{9}+\frac{2}{3} \\ =\frac{2}{9}+\frac{6}{9}(Changing\frac{2}{3}toequivalentfractionthathavesamedenominator) \\ =\frac{2+6}{9} \\ =\frac{8}{9} \end{gathered}$$

Therefore the required sum in the lowest term is $\frac{8}{9}$