Add. Write each sum in the lowest terms.

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Solution

We have $\frac{3}{4} + \frac{1}{5}$
The least common multiple of the denominators $(4, 5) = 20 (g i v e n)$
$\frac{3}{4} + \frac{1}{5} = \frac{15}{20} + \frac{4}{20} (c h a n g i n g \frac{3}{4} & \frac{1}{5} i n e q u i v a l e n t f r a c t i o n h a v i n g d e n o m i n a t o r a s 20) = \frac{15 + 4}{20} = \frac{19}{20}$
Therefore, the required sum in the lowest term is $\frac{19}{20}$ .

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