Addition of HBr to which alkene gives only one type of product

$C H_{3} - C H = C H - C H_{3}$

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$C H_{3} - C H = C H_{2}$

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Both b & c

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Solution

The correct option is A
$C H_{3} - C H = C H - C H_{3}$

Symmetrical alkene gives one product

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Addition of HBr to which alkene gives only one type of product

The correct option is A CH3−CH=CH−CH3 Symmetrical alkene gives one product

The correct option is A
$C H_{3} - C H = C H - C H_{3}$

Symmetrical alkene gives one product