The reaction of one equivalent of HBr with CH 3- CH - C - CH gives-D- CH 2- CH - C - CBr

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The reaction ...

Question

The reaction of one equivalent of HBr with
$C H_{3} = C H - C \equiv C H$ gives:

C H_{2} = C H - C \equiv C B r

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C H_{2} = C H - C | B r = C H_{2}

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C H_{3} - C | B r H - C \equiv C H

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C H_{2} = C H - C H \equiv C H B r

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Solution

The correct option is B $C H_{2} = C H - C | B r = C H_{2}$
Here, double bond and triple bond are in conjugation. So, triple bond is more reactive due to more stable carbocation.

So, the reaction product will be $C H_{2} = C H - C | B r = C H_{2}$

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A straight chain hydrocarbon has the molecular formula C8H10. The hybridisation for the carbon atoms from one end of the chain to the other are respectively $s p^{3}, s p^{2}, s p^{2}, s p^{3}, s p^{2}, s p^{2}, s p$ and $s p$ . The structural formula of the hydrocarbon would be

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The reaction of one equivalent of HBr with CH3=CH−C≡CH gives:

The correct option is B CH2=CH−C|Br=CH2Here, double bond and triple bond are in conjugation. So, triple bond is more reactive due to more stable carbocation. So, the reaction product will be CH2=CH−C|Br=CH2

The reaction of one equivalent of HBr with
$C H_{3} = C H - C \equiv C H$ gives:

The correct option is B $C H_{2} = C H - C | B r = C H_{2}$
Here, double bond and triple bond are in conjugation. So, triple bond is more reactive due to more stable carbocation.

So, the reaction product will be $C H_{2} = C H - C | B r = C H_{2}$