The correct sequence of decrease in the bond angles of the following hydrides is
NH3> PH3> AsH3> SbH3
NH3> AsH3> PH3> SbH3
SbH3> AsH3> PH3> NH3
PH3> NH3> AsH3> SbH3
Q. When the hybridization state of carbon atom changes from sp3 to sp2 and finally to sp, the angle between the hybridized orbitals:
Q. H - B - H bond angle in BH−4 is:
Bond angle is defined as the angle between the orbitals containing bonding electron pairs around the central atom in a molecule/complex ion. (True/False)
In the given molecule choose the correct order of their angle.
x = y = z
can't be predicted
x > y > z
x < y < z
The correct order of bond angles (smallest first) in H2S, NH3, BF3 and SiH4 is-
Q. Bond angle is defined as the angle between the orbitals containing bonding electron pairs around the central atom in a molecule
Q. Which of the following arrangements correctly represents the decreasing order of bond angles?
Which bond angle will result in maximum dipole moment for XY2?
θ = 180°
θ = 150°
θ = 120°
Q. What is/are the correct option(s) about ClO2?
- It has one odd electron and dimerizes to form Cl2O4 which exists as Cl+ClO−4
- It has bond angle more than OCl2
- It can be prepared by reaction of KClO3 with oxalic acid
- It is 10 times more soluble in water than chlorine because it hydrolyzes more readily than Cl2