Question

Arrange the bond angle order of ${\mathrm{NO}}_2$, ${{\mathrm{NO}}_2}^{-}$, ${{\mathrm{NO}}_2}^{+}$,${{\mathrm{NO}}_3}^{-}$ in descending manner.

Answer 1

Bond angle

• The angle produced between two covalent bonds that originate from the same atom is known as the bond angle.
• The state of hybridization of the central atom determines the bond angle.
• There are two lone pairs in the water.
• The measured bond angle is $104.8°$.
• The more electronegative the central atom, the more will be the bond angle.

Bond angle order:

• The repulsion between bond pairs grows as the number of lone pairs of electrons increases, and they tend to become closer.
• The electronegativity of the core atom rises as a result of this repulsion, and the bond angle decreases.
• The arrangement of bond angles in descending order

${{\mathrm{NO}}_2}^{-}<{{\mathrm{NO}}_3}^{-}<{\mathrm{NO}}_2<{{\mathrm{NO}}_2}^{+}$