Question

Addition of $KI$ drop by drop to $AgN{O}_3$ aqueous solution gives an impure sol of $AgI$. The impurities needed not to be removed by dialysis is :

• A. suspended state of $AgI$
• B. excess of $AgN{O}_{3(aq.)}$
• C. excess of $K{I}_{(aq.)}$
• D. excess of $KN{O}_{3(aq.)}$

Answer 1

The correct option is A suspended state of $AgI$

Dialysis is used to remove soluble impurities present in solution. The sol contains AgI which will not be easily removed.