Question

When excess of $AgN{O}_3$ is treated with $KI$ solution, $AgI$ forms :

• A. +ve charged sol
• B. -ve charged sol
• C. neutral sol
• D. true solution

Answer 1

The correct option is A +ve charged sol

If $AgN{O}_3$ is added to $KI$ medium, negatively charged sol is formed due to adsorption of iodide ions from $KI$ onto the $AgI$ precipitate.

If $KI$ is added to $AgN{O}_3$, postive sol is formed due to $A{g}^{+}$ ions in solution which get adsorbed on $AgI$.