When excess of AgNO 3 is treated with KI solution- AgI forms-A- -vely charged solB- -ve charge solC- Neutral solD- True solution

The correct option is B +ve charge sol nbsp;AgNO_3 (excess) + KI → nbsp;Agl AgI/Ag^+ Here, excess Ag^+ is adsorbed on solid AgI and forms a positvely cha ...

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Standard XII

Chemistry

Classification of Colloids - Based on Phases

When excess o...

Question

When excess of $A g N O_{3}$ is treated with $K I$ solution, $A g I$ forms:

+ve charge sol

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-vely charged sol

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Neutral sol

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True solution

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Solution

The correct option is A +ve charge sol
$A g N O_{3} (excess) + K I \to A g l + A g N O_{3} (remaining) - ------------ \to A g I / A g^{+}$
Here, excess $A g^{+}$ is adsorbed on solid $A g I$ and forms a positvely charged sol.

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When excess of AgNO3 is treated with KI solution, AgI forms:

The correct option is A +ve charge sol AgNO3 (excess)+KI→Agl+AgNO3 (remaining)−−−−−−−−−−−−−→AgI/Ag+ Here, excess Ag+ is adsorbed on solid AgI and forms a positvely charged sol.

When excess of $A g N O_{3}$ is treated with $K I$ solution, $A g I$ forms:

The correct option is A +ve charge sol
$A g N O_{3} (excess) + K I \to A g l + A g N O_{3} (remaining) - ------------ \to A g I / A g^{+}$
Here, excess $A g^{+}$ is adsorbed on solid $A g I$ and forms a positvely charged sol.