Question

Additive inverse of $(4\times -5)$ is

• A. $-20$
• B. $20$
• C. $4$
• D. $1$

Answer 1

The correct option is B $20$

$(4\times -5)=-20$

Let additive inverse of $-20$ be $x$.

$-20+x=0$

$\therefore x=20$