Additive inverse of the following complex
$(- 6, 5) + (10, - 4)$

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Solution

$(- 6, 5) + (10, - 4) \equiv (- 6 + 10, 5 - 4) \equiv (4, 1)$
Additive inverse of $4 + i = 4 - i$

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Similar questions

4 - 3 i

\frac{8}{5}, \frac{6}{10}, \frac{- 3}{8}, \frac{- 16}{3}, \frac{- 4}{1}

Calculate: -10 + 4 - 5 + 2 .
What will be the additive inverse of the resultant?

The additive inverse of an integer x is given by -x.

Therefore, the additive inverse of -10 is -(-10) = 10

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