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Question

Adjacent figure shows the force-displacement graph of a moving body, the work done in displacing body from x=0 to x=35m is equal to
1074696_35c6ec163e374597b8707c3b2c1abb06.png

A
50 J
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B
25 J
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C
287.5 J
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D
200 J
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Solution

The correct option is C 287.5 J
Work done = (Shaded area under the graph between x=0 to $ x = 35 m)
Work done = Area of triangle (0 to 10s)+Area of rectangle (10 to 30s)+Area of trapezium(30 to 35s)

W=(12×10×10)+(20×10)+(12×(10+5)×5)

=287.5J

1702684_1074696_ans_c1a3b18854fc4c39b7763547333bd1e8.png

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