Aforce of 1200 newton acts on surface of area 10 cm square, normally what would be the pressure applied on the surface?

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Solution

Given,
Force= F = 1200 N
Area = A =10 cm² =
We know,

Pressure = $fraction numerator F o r c e over denominator A r e a end fraction$ == pascal

As the bar is also a unit of pressure where 1 pascal equal to bar
so, pascal = 12 bar

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Aforce of 1200 newton acts on surface of area 10 cm square, normally what would be the pressure applied on the surface?

Given, Force= F = 1200 N Area = A =10 cm² = We know, Pressure = == pascal As the bar is also a unit of pressure where 1 pascal equal to bar so, pascal = 12 bar

Given,
Force= F = 1200 N
Area = A =10 cm² =
We know,

Pressure = $fraction numerator F o r c e over denominator A r e a end fraction$ == pascal

As the bar is also a unit of pressure where 1 pascal equal to bar
so, pascal = 12 bar