After applying invertendo to 3:7::2:9 we get
(i) 37+−49−−117−79(ii) 23+−45−13−25(iii) 47−−89−−137+179
(7a2−63b2)=?(a) (7a−9b)(9a+7b)(b) (7a−9b)(7a+9b)(c) 9(a−3b)(a+3b)(d) 7(a−3b)(a+3b)