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Question

What should be added to 6a3+5a2a27 to get 9a22aa3+2?

A
5a3+7a23a+5
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B
7a311a2+7a9
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C
7a3+11a27a+9
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D
5a3+9a25a+3
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Solution

The correct option is C 7a3+11a27a+9
Let 'y' be the term to be added to 6a3+5a2a27 to get 9a22aa3+2
= 6a3+5a2a27+y=9a22aa3+2
Subtracting 6a3+5a2a27 from 9a22aa3+2,
= (a3+9a22a+2) - (6a32a2+5a7)
= (a36a3)+(9a2+2a2)+(2a5a)+(2+7),
= 7a3+11a27a+9

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