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Byju's Answer
Standard VI
Mathematics
Solving Unknowns
After balanci...
Question
After balancing the equation,
K
2
C
r
2
O
7
+
X
H
2
S
O
4
+
Y
S
O
2
→
K
2
S
O
4
+
C
r
2
(
S
O
4
)
3
+
Z
H
2
O
The values of X, Y and Z obtained will be respectively.
A
1
,
3
,
1
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B
2
,
2
,
1
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C
1
,
1
,
3
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D
1
,
2
,
1
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Solution
The correct option is
A
1
,
3
,
1
Suggest Corrections
0
Similar questions
Q.
In the chemical reaction,
K
2
C
r
2
O
7
+
x
H
2
S
O
4
+
y
S
O
2
⟶
K
2
S
O
4
+
C
r
2
(
S
O
4
)
3
+
z
H
2
O
x
,
y
and
z
are, respectively
:
Q.
In the chemical reaction,
K
2
C
r
2
O
7
+
x
H
2
S
O
4
+
y
S
O
2
→
K
2
S
O
4
+
C
r
2
(
S
O
4
)
3
+
z
H
2
O
. the values of x, y and z respectively are.
Q.
In the chemical reaction,
K
2
C
r
2
O
7
+
X
H
2
S
O
4
+
Y
S
O
2
→
K
2
S
O
4
+
C
r
(
S
O
4
)
3
+
z
H
2
O
,
X
,
Y
and
Z
are respectively,
Q.
In the chemical reaction,
K
2
C
r
2
O
7
+
x
H
2
S
O
4
+
y
S
O
2
→
K
2
S
O
4
+
C
r
2
(
S
O
4
)
3
+
z
H
2
O
the value of x+y+z:
Q.
For the oxidation-reduction reaction;
K
2
C
r
2
O
7
+
X
H
2
S
O
4
+
Y
S
O
2
→
K
2
S
O
4
+
C
r
2
(
S
O
4
)
3
+
Z
H
2
O
The values X, Y and Z are:
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