After recording the height and weight, Ted wanted to know who is taller? Him or Ned. For that, he asked Ned’s height. He told that it was 135 cm and Ted’s height was 4.5 ft. Given 1 foot = 0.3 meters, what will be the value of $\frac{Ned's height}{Ted's height}$ ?

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Solution

The correct option is C
1

To compare two similar quantities, their units must be same. Ned’s height is in cm and Ted’s height is in ft. In order to compare those heights, we need to convert both the heights to same units.
Thus, $4.5 f t = 4.5 \times 0.3 m = 1.35 m$
Now, 1m = 100 cm
Thus, $4.5 f t = 1.35 m = 1.35 \times 100 c m = 135 c m$
Thus, $\frac{Ned's height}{Ted's height} = \frac{135}{135} = 1$

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After recording the height and weight, Ted wanted to know who is taller? Him or Ned. For that, he asked Ned’s height. He told that it was 135 cm and Ted’s height was 4.5 ft. Given 1 foot = 0.3 meters, what will be the value of Ned's heightTed's height?

After recording the height and weight, Ted wanted to know who is taller? Him or Ned. For that, he asked Ned’s height. He told that it was 135 cm and Ted’s height was 4.5 ft. Given 1 foot = 0.3 meters, what will be the value of $\frac{Ned's height}{Ted's height}$ ?