After some time number of radioactive nuclei of an isotope become constant at $\frac{A B}{I n (2)}$ where B is the half time and A is the rate at which radioactive isotope is produced. A is (when nuclei has become constant)

increasing exponentially

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decreasing exponentially

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constant

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dependent upon decay constant

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Solution

The correct option is C
constant

Given $N = \frac{A B}{I n (2)} = \frac{A}{\frac{I n (2)}{B}} = \frac{A}{λ} o r, A = λ N$

Since, N is constant, A will be constant

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After some time number of radioactive nuclei of an isotope become constant at ABIn(2) where B is the half time and A is the rate at which radioactive isotope is produced. A is (when nuclei has become constant)

The correct option is C constant Given N=ABIn(2)=AIn(2)B=Aλor,A=λN Since, N is constant, A will be constant

After some time number of radioactive nuclei of an isotope become constant at $\frac{A B}{I n (2)}$ where B is the half time and A is the rate at which radioactive isotope is produced. A is (when nuclei has become constant)

The correct option is C
constant

Given $N = \frac{A B}{I n (2)} = \frac{A}{\frac{I n (2)}{B}} = \frac{A}{λ} o r, A = λ N$

Since, N is constant, A will be constant