You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Mathematics

Application of Direct Proportionality

AgNO3 sample ...

Question

$A g N O_{3}$ sample is $73 %$ by mass. To prepare $125 m L$ of $0.04 M A g N O_{3}$ solution, $A g N O_{3}$ sample required is

1.471 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.063 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.250 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.164 g

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $1.164 g$
$125 m L of 0.04 M A g N O_{3} = 125 \times 0.04 millimoles$
$= \frac{125 \times 0.04}{1000} m o l$
$Molar mass of A g N O_{3} = 170 g / m o l$
$weight of pure A g N O_{3} = \frac{125 \times 0.04 \times 170}{1000} g$

It is given in the question that $A g N O_{3}$ is $73 %$ by mass which means $100 g A g N O_{3}$ sample contains $73 g$ pure $A g N O_{3}$

$∴ Total weight of sample required = \frac{125 \times 0.04 \times 170 \times 100}{1000 \times 73} g$
$= 1.164 g$

Suggest Corrections

Similar questions

Silver nitrate is 85% by mass. To prepare 125ml of 0.05molar silver nitrate solution , silver nitrate sample required is?

3.0

g sample of

K O C l

and

C a O C l_{2}

is dissolved in water to prepare

100

mL solution which requires

100

mL of

0.15 M

acidified

K_{2} C_{2} O_{4}

for end point. The clear solution is now treated with excess of

A g N O_{3}

solution which precipitates

2.87

g of

A g C l

. The mass percentage of

K O C l

and

C a O C l_{2}

in the mixture is :

1

g sample of

A g N O_{3}

is dissolved in

50

mL of water. It is titrated with

50

mL of

K I

solution. The

A g I

precipitated is filtered off. Excess of

K l

in filtrate is titrated with

\frac{M}{10}

K I O_{3}

in presence of

6 M H C l

till all

I^{-}

converted into

I C l

. It requires

50

mL of

\frac{M}{10}

K I O_{3}

solution.

20

mL of the same stock solution of

K I

requires

30

mL of

\frac{M}{10}

K I O_{3}

A g N O_{3}

in sample. The reaction is given below:

K I O_{3} + 2 K I + 6 H C l ⟶ 3 I C l + 3 K C l + 3 H_{2} O

Q. The amount of

M g

required to replace

A g

from 500 ml of 0.5 M

A g N O_{3}

solution is:

Q. If

12

drops of

A g N O_{3}

solution are used to reach the colour point, what mass of chloride ion is present in one litre sample?

Join BYJU'S Learning Program

Explore more

Application of Direct Proportionality

Standard IX Mathematics

Join BYJU'S Learning Program

AgNO3 sample is 73% by mass. To prepare 125 mL of 0.04 M AgNO3 solution, AgNO3 sample required is

$A g N O_{3}$ sample is $73 %$ by mass. To prepare $125 m L$ of $0.04 M A g N O_{3}$ solution, $A g N O_{3}$ sample required is