Question

# Air contains nearly 20% oxygen by volume. The volume of air needed for complete combustion of 100 ml of acetylene will be :

A
500 ml
B
100 ml
C
250 ml
D
1250 ml

Solution

## The correct option is D 1250 ml$$2C_2H_2 + 5O_2 \longrightarrow 4CO_2 + 2H_2O$$2 moles of $$C_2H_2$$ react with 5 moles of $$O_2$$1 moles of $$C_2H_2= 22400ml$$100 ml of $$C_2H_2 = \dfrac{100}{22400}= 4.46\times 10^{-3} mole$$2 moles of $$C_2H_2$$ react with 5 moles of $$O_2$$4.46$$\times 10^{-3}$$ moles of $$C_2H_2$$  will react with $$\dfrac{4.46\times10^{-3}\times5}{2}$$ = 0.0112 moles of $$O_2$$$$0.0112 \times22400$$  = 250 ml of $$O_2$$Since air contains nearly 20% oxygen by volume. The volume of air needed for complete combustion of 100 ml of acetylene =$$\dfrac{250\times 100}{20}= 1250 ml$$.Hence,option D is correct.Chemistry

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