Question

Ajay is $36$ years older than his son . After $10$ years , Ajay will be three times as old as his son . Find their present ages.

Answer 1

Let son’s present age is $x$ years and Ajay’s age is $\left(x+36\right)$ years

After $10$ years,

$\begin{array}{rcl}\left(x+36\right)+10& =& 3\left(x+10\right)\\ x+46& =& 3x+30\\ 3x-x& =& 46-30\\ 2x& =& 16\\ x& =& \frac{16}{2}\\ x& =& 8\end{array}$

Ajay’s age is $8+36=44$

Son’s age is $8$ years

Hence , the required age of Ajay and Ajay son's is $44$years and $8$years respectively.