Question 72
Ajita starts off from home at 07.00 h with her father on a scooter that goes at a uniform speed of 30 km/h and drops her at her school after half an hour. She stays in the school till 13.30 h and takes an auto rickshaw to return home. The rickshaw has a uniform speed of 10km/h. Draw the graph of the above situation and also determine the distance of Ajita's school from her house.

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Solution

Speed of Ajita's father on scooter = 30km/h
Time taken by her father to drop Ajita to her school= $\frac{1}{2} h o r 30 m i n$
$∴$ Distance between Ajita's school and her home = $30 \times \frac{1}{2} = 15 k m$ [ $∵ d i s t a n c e = s p e e d \times t i m e$ ]

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Speed of Ajita's father on scooter = 30km/h Time taken by her father to drop Ajita to her school= 12h or 30 min ∴ Distance between Ajita's school and her home =30×12=15 km [∵distance=speed×time ]

Speed of Ajita's father on scooter = 30km/h
Time taken by her father to drop Ajita to her school= $\frac{1}{2} h o r 30 m i n$
$∴$ Distance between Ajita's school and her home = $30 \times \frac{1}{2} = 15 k m$ [ $∵ d i s t a n c e = s p e e d \times t i m e$ ]