Question

Akash takes 30 min to reach his school from his home by walking at a constant speed if he walks at 3/5 of the orignal canstant speed then how much more time would he take to reach the school

Answer 1

Dear Student,

$$\begin{gathered} \mathrm{Let}\mathrm{the}\mathrm{original}\mathrm{constant}\mathrm{speed}\mathrm{of}\mathrm{walking}=\mathrm{x}\mathrm{m}/\min \\ \mathrm{Time}\mathrm{taken}\mathrm{to}\mathrm{reach}\mathrm{the}\mathrm{school}=30\min \\ \mathrm{Distance}\mathrm{of}\mathrm{the}\mathrm{school}=\mathrm{speed}\times \mathrm{time}=\mathrm{x}\times 30=30\mathrm{x}\mathrm{m} \\ \mathrm{Now},\mathrm{new}\mathrm{speed}=\frac{3}{5}\mathrm{of}\mathrm{x}\mathrm{m}/\min =\frac{3\mathrm{x}}{5}\mathrm{m}/\min \\ \mathrm{Distance}\mathrm{to}\mathrm{be}\mathrm{travelled}=30\mathrm{x}\mathrm{m} \\ \mathrm{Time}\mathrm{taken}\mathrm{with}\mathrm{new}\mathrm{speed}=\frac{\mathrm{Distance}}{\mathrm{Speed}}=\frac{30\mathrm{x}}{3\mathrm{x}/5}=50\min \\ \mathrm{So},\mathrm{Akash}\mathrm{will}\mathrm{take}20\mathrm{more}\mathrm{minutes}\mathrm{to}\mathrm{reach}\mathrm{the}\mathrm{school}\mathrm{with}\mathrm{new}\mathrm{speed}. \end{gathered}$$

Regards