Al and KClO3 react together to form Al2O3 according to the following reactions : 2KClO3⟶2KCl+3O2 4Al+3O2⟶2AI2O3 4 moles of KClO3 (50% pure) on reaction with excess of Al forms _______ moles of Al2O3.
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Solution
2KClO3⟶2KCl+3O2 4Al+3O2⟶2Al2O3 According to balance reaction 2 mole of KClO3 forms 2 moles of Al2O3.