Alk. $K M n O_{4}$ will oxidise acytylene to :

Ethylene glycol

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Ethyl alcohol

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Oxalic acid

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Acetic acid

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Solution

The correct option is C Oxalic acid
$H - C \equiv C - H + 2 (0) a l k - K M n O_{4} - ------- \to$
$C H O | C H O 2 (0) - ---- \to K M n O_{4} C O O H | C O O H$

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