Alkyl cyanides $({C H}_{3} C N)$ when treated with hydrogen in presence of $P t$ or with $L i A l H_{4}$ produces same carbon number compound. What is the formula of that compound?

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Solution

$H_{3} C - C H_{2} - C H_{2} - C \equiv N + 2 H_{2} P d / c - ------ \to H_{3} C - C H_{2} - C H_{2} - N H_{2}$
This is reduction of nitrile to give amines
$H_{3} C - C \equiv N + 2 H_{2} L i A l H_{4} - ------- \to P t H_{3} C - C H_{2} - N H_{2}$
Or
${C_{2} H}_{3} N + 2 H_{2} L i A l H_{4} - ------- \to P t C_{2} H_{7} N$
Thus the formula of the compound is $C H_{3} - C H_{2} - N H_{2}$

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