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Question

All complex numbers z which satisfy the equation ∣∣∣z−6iz+6i∣∣∣=1 lie on the

A
Imaginary axis
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B
Real axis
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C
Neither of the axes
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D
None of these
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Solution

The correct option is B Real axis
We have, z6iz+6i=1
or, |z6i|=|z+6i|
Let z=x+iy
or, |x+iy6i|=|x+iy+6i|
or, |x+(y6)i|=|x+(y+6)i|
or, x2+(y6)2=x2+(y+6)2
or, x2+(y6)2=x2+(y+6)2
or, y2+3612y=y2+36+12y
or, 24y=0
or, y=0
Hence, B is the correct option.

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