All possible values of x when |3x -4| = 11 are

$+ 5, \frac{7}{3}$

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$+ 5, - \frac{7}{3}$

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$- 5, \frac{7}{3}$

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$- 5, - \frac{7}{3}$

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Solution

The correct option is B
$+ 5, - \frac{7}{3}$

Given, |3x -4| = 11

$\Rightarrow 3 x - 4 = + 11$ or $3 x - 4 = - 11$

For $3 x - 4 = + 11$

$\Rightarrow 3 x = + 11 + 4$

$\Rightarrow 3 x = + 15$

$\Rightarrow x = + 5$

For, $3 x - 4 = - 11$

$\Rightarrow 3 x = - 11 + 4$

$\Rightarrow 3 x = - 7$

$\Rightarrow x = \frac{- 7}{3}$

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