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Catalytic Hydrogenation

α- chloroprop...

Question

$α -$ chloropropanoic acid on treatment with alcoholic KOH followed by acidification gives:

C H_{3} - C H (O H) - C O O H

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C H_{2} = C H - C O O H

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H O - C H_{2} - C H_{2} - C O O H

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C H_{3} - C H_{2} - C O O H

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Solution

The correct option is B $C H_{2} = C H - C O O H$
$α -$ chloropropanoic acid on treatment with alcoholic $K O H$ followed by acidification gives $C H_{2} = C H - C O O H$ . A molecule of $H C l$ is eliminated. It is an example of dehydrohalogenation reaction.

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(A) C H_{3} - C H_{2} - C | C O O H H - - C H - C H_{3}

(B) C H_{3} - C | C O O H H - C H_{2} - - C H - C H_{3}

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