Although $[N i (C O)_{4}]$ has tetrahedral geometry, it is diamagnetic. Explain.

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Solution

$N i$ is diamagenetic as the $C O$ is a strong field ligand that cause back-bonding that's why all electrons are paired.

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[NiCl₄]²⁻ is paramagnetic while [Ni(CO)₄] is diamagnetic though both are tetrahedral. Why?

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