Question

On valence bond theory the geometry of $Ni{\left(CO\right)}_4$ is tetrahedral.

• A. True
• B. False

Answer 1

The correct option is A True

In $Ni(CO{)}_4$, $Ni$ is in zero oxidation state.

Outermost orbital of $Ni$

Here $3d$ has one empty sub-orbital. This is because of tetrahedral geometry and diamagnetic. Since $Ni$ is in zero oxidation state.