Aluminium chloride exists as a dimer ( $A l_{2} C l_{6}$ ) in solid state as well as in solution of non-polar solvents such as $C_{6} H_{6}$ . When dissolved in water it gives:

$A l_{2} O_{3} + 6 H C l$

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$[A l (C H_{2} O)_{6}] + 3 C l^{-}$

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$[A l (O H)_{6}]^{3 -} + 3 H C l$

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$A l^{+ 3} + 3 C l^{-}$

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Solution

The correct option is C
$[A l (O H)_{6}]^{3 -} + 3 H C l$

$A l C l_{3} + 6 H_{2} O \to [A l (O H)_{6}]^{3 -} + 3 H C l$

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Similar questions

Q. Aluminium chloride exists as dimer,

A l_{2} C l_{6}

in solid state as well as in solution of non-polar solvents such as benzene. When dissolved in water, it gives:

Q. Aluminum chloride exists as a dimer

A l_{2} C l_{6}

in solid state as well as in solution of non-polar solvents such as

C_{6} H_{6}

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Aluminium chloride exists as a dimer ( $A l_{2} C l_{6}$ ) in solid state as well as in solution of non-polar solvents such as $C_{6} H_{6}$ . When dissolved in water it gives:

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Q. Aluminimum chloride exists as dimer,

A l_{2} C l_{6}

, in solid state as well as in solution of non-polar solvents such as benzene. When dissolved in water, it gives :

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Aluminium chloride exists as a dimer (Al2Cl6) in solid state as well as in solution of non-polar solvents such as C6H6. When dissolved in water it gives:

The correct option is C [Al(OH)6]3−+3HCl AlCl3+6H2O→[Al(OH)6]3−+3HCl

Aluminium chloride exists as a dimer ( $A l_{2} C l_{6}$ ) in solid state as well as in solution of non-polar solvents such as $C_{6} H_{6}$ . When dissolved in water it gives:

The correct option is C
$[A l (O H)_{6}]^{3 -} + 3 H C l$

$A l C l_{3} + 6 H_{2} O \to [A l (O H)_{6}]^{3 -} + 3 H C l$