Aluminum chloride exists as a dimer $A l_{2} C l_{6}$ solid state as well as in solution of non-polar solvents such as $C_{5} H_{5}$ . When dissolved in water, it gives:

A l_{2} O_{3} + 6 H C l

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[A l (H_{2} O)_{6}]^{+} + 3 C l^{-}

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[A l (O H)_{6}]^{3 -} + 6 H C l

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A l^{3 +} + 3 C l^{-}

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Solution

The correct option is B $[A l (H_{2} O)_{6}]^{+} + 3 C l^{-}$
$A l C l_{3}$ is a covalent in nature but due to high hydration energy of $A l^{+ 3}$ it acts as an ionic compound in Water.
$A l^{3 +}$ has high hydration energy because of its small size and high charge density which are related to hydration energy as inversely proportional to size directly proportional to charge density.
Equations:
${A l}_{2} {C l}_{6} + 6 H_{2} O ⟶ {[Al {(H_{2} O)}_{6}]}_{6}^{3 +} + 3 {C l}^{-}$
${A l}_{2} {C l}_{6} + 12 H_{2} O ⟶ 2 {[A l {(H_{2} O)}_{6}]}_{6}^{+ 3} + 6 C l^{-}$
Option: $B$

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