Question

amisha isn years old bobby her brother is 9 years older than amishatheir mother is 3 times as old as amishatheir father is twice old as bobby if the sum of the ages of 4 members is 132 find their ages

Answer 1

$$\begin{gathered} \mathrm{Let}\mathrm{age}\mathrm{of}\mathrm{amisha}=\mathrm{n}\mathrm{years} \\ \mathrm{Age}\mathrm{of}\mathrm{brother}=\mathrm{n}+9\mathrm{years} \\ \mathrm{Age}\mathrm{of}\mathrm{mother}=3\mathrm{n} \\ \mathrm{Age}\mathrm{of}\mathrm{father}=2\left(\mathrm{n}+9\right) \\ \mathrm{according}\mathrm{to}\mathrm{question}\mathrm{sum}\mathrm{of}\mathrm{ages}\mathrm{of}\mathrm{family}=132 \\ \mathrm{n}+\mathrm{n}+9+3\mathrm{n}+2\left(\mathrm{n}+9\right)=132 \\ 7\mathrm{n}+9+18=132 \\ 7\mathrm{n}=132-27 \\ 7\mathrm{n}=105 \\ \mathrm{n}=15\mathrm{years} \\ \mathrm{amisha}\text{'}\mathrm{s}\mathrm{age}=15\mathrm{years} \\ \mathrm{brother}\text{'}\mathrm{s}\mathrm{age}=\mathrm{n}+9=24\mathrm{years} \\ \mathrm{Mother}\text{'}\mathrm{s}\mathrm{age}=3\mathrm{n}=3\times 15=45\mathrm{years} \\ \mathrm{Father}\text{'}\mathrm{s}\mathrm{age}=2\left(\mathrm{n}+9\right)=2\times 24=48\mathrm{years} \end{gathered}$$